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To:Speakup is a screen review system for Linux. From:Tyler Spivey Subject:Re: ot, bash programming question Date:Thu, 29 Mar 2012 00:24:38 -0700
 

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I'm not quite sure what you're asking, maybe this is it.
True returns 0 by default, so you can just do:
if true;then
echo it succeeded
fi
But from your example script, maybe you wanted:
if ! true;then
echo it failed
fi


On 3/28/2012 11:45 PM, Gregory Nowak wrote:
> Hi folks,
>
> apologies for the off topic post, but I'm hoping someone can answer
> my question.
>
> In a bash script, how do you deal with a program returning 0 in an
> if statement? Here's a script to illustrate what I mean
>
> #!/bin/sh if [ `/bin/true || echo $?` = 1 ] ; then echo "returned
> 1" fi
>
> When I run this, I should just get the bash prompt back. When I run
> it though, I get:
>
> [: 4: =: unexpected operator
>
> followed by the prompt. I understand this happens because true
> exits with 0 status, and it isn't echoed back, so the if statement
> compares nothing to 1. What I'd like to know is how to get around
> that? Thanks in advance.
>
> Greg
>
>
> _______________________________________________ Speakup mailing
> list Speakup@braille.uwo.ca
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